Solve for x
x=2y+\frac{13}{3}
Solve for y
y=\frac{x}{2}-\frac{13}{6}
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3x-6y-12=1
The factorial of 0 is 1.
3x-12=1+6y
Add 6y to both sides.
3x=1+6y+12
Add 12 to both sides.
3x=13+6y
Add 1 and 12 to get 13.
3x=6y+13
The equation is in standard form.
\frac{3x}{3}=\frac{6y+13}{3}
Divide both sides by 3.
x=\frac{6y+13}{3}
Dividing by 3 undoes the multiplication by 3.
x=2y+\frac{13}{3}
Divide 13+6y by 3.
3x-6y-12=1
The factorial of 0 is 1.
-6y-12=1-3x
Subtract 3x from both sides.
-6y=1-3x+12
Add 12 to both sides.
-6y=13-3x
Add 1 and 12 to get 13.
\frac{-6y}{-6}=\frac{13-3x}{-6}
Divide both sides by -6.
y=\frac{13-3x}{-6}
Dividing by -6 undoes the multiplication by -6.
y=\frac{x}{2}-\frac{13}{6}
Divide 13-3x by -6.
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