Solve 3x-6y^2+4=0

$$3 x - 6 y ^ { 2 } + 4 = 0$$

Solve for x

$$x=2y^{2}-\frac{4}{3}$$

Steps for Solving Linear Equation

Add 6y^{2} to both sides. Anything plus zero gives itself.

$$3x+4=6y^{2}$$

Subtract 4 from both sides.

$$3x=6y^{2}-4$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{6y^{2}-4}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{6y^{2}-4}{3}$$

Divide 6y^{2}-4 by 3.

$$x=2y^{2}-\frac{4}{3}$$

Solve for y (complex solution)

$$y=-\frac{\sqrt{18x+24}}{6}$$

$$y=\frac{\sqrt{18x+24}}{6}$$

Solve for y

$$y=\frac{\sqrt{18x+24}}{6}$$

$$y=-\frac{\sqrt{18x+24}}{6}\text{, }x\geq -\frac{4}{3}$$