Solve for x
x=\frac{7}{3\left(1-2y\right)}
y\neq \frac{1}{2}
Solve for y
y=\frac{1}{2}-\frac{7}{6x}
x\neq 0
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\left(3-6y\right)x=7
Combine all terms containing x.
\frac{\left(3-6y\right)x}{3-6y}=\frac{7}{3-6y}
Divide both sides by 3-6y.
x=\frac{7}{3-6y}
Dividing by 3-6y undoes the multiplication by 3-6y.
x=\frac{7}{3\left(1-2y\right)}
Divide 7 by 3-6y.
-6xy=7-3x
Subtract 3x from both sides.
\left(-6x\right)y=7-3x
The equation is in standard form.
\frac{\left(-6x\right)y}{-6x}=\frac{7-3x}{-6x}
Divide both sides by -6x.
y=\frac{7-3x}{-6x}
Dividing by -6x undoes the multiplication by -6x.
y=\frac{1}{2}-\frac{7}{6x}
Divide 7-3x by -6x.
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