Solve for x
x=\frac{5\left(y-7\right)}{3}
Solve for y
y=\frac{3x}{5}+7
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3x=-35+5y
Add 5y to both sides.
3x=5y-35
The equation is in standard form.
\frac{3x}{3}=\frac{5y-35}{3}
Divide both sides by 3.
x=\frac{5y-35}{3}
Dividing by 3 undoes the multiplication by 3.
-5y=-35-3x
Subtract 3x from both sides.
-5y=-3x-35
The equation is in standard form.
\frac{-5y}{-5}=\frac{-3x-35}{-5}
Divide both sides by -5.
y=\frac{-3x-35}{-5}
Dividing by -5 undoes the multiplication by -5.
y=\frac{3x}{5}+7
Divide -35-3x by -5.
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