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3x+1=5y
Add 5y to both sides. Anything plus zero gives itself.
3x=5y-1
Subtract 1 from both sides.
\frac{3x}{3}=\frac{5y-1}{3}
Divide both sides by 3.
x=\frac{5y-1}{3}
Dividing by 3 undoes the multiplication by 3.
-5y+1=-3x
Subtract 3x from both sides. Anything subtracted from zero gives its negation.
-5y=-3x-1
Subtract 1 from both sides.
\frac{-5y}{-5}=\frac{-3x-1}{-5}
Divide both sides by -5.
y=\frac{-3x-1}{-5}
Dividing by -5 undoes the multiplication by -5.
y=\frac{3x+1}{5}
Divide -3x-1 by -5.