Solve 3x-4y-12=0

$$3 x - 4 y - 12 = 0$$

Solve for x

$$x=\frac{4\left(y+3\right)}{3}$$

Steps for Solving Linear Equation

Add 4y to both sides. Anything plus zero gives itself.

$$3x-12=4y$$

Add 12 to both sides.

$$3x=4y+12$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{4y+12}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{4y+12}{3}$$

Divide 12+4y by 3.

$$x=\frac{4y}{3}+4$$

Solve for y

$$y=\frac{3\left(x-4\right)}{4}$$

Steps for Solving Linear Equation

Subtract 3x from both sides. Anything subtracted from zero gives its negation.

$$-4y-12=-3x$$

Add 12 to both sides.

$$-4y=-3x+12$$

The equation is in standard form.

$$-4y=12-3x$$

Divide both sides by -4.

$$\frac{-4y}{-4}=\frac{12-3x}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$y=\frac{12-3x}{-4}$$

Divide -3x+12 by -4.

$$y=\frac{3x}{4}-3$$