Solve for x
x=\frac{4\left(y+3\right)}{3}
Solve for y
y=\frac{3\left(x-4\right)}{4}
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3x=12+4y
Add 4y to both sides.
3x=4y+12
The equation is in standard form.
\frac{3x}{3}=\frac{4y+12}{3}
Divide both sides by 3.
x=\frac{4y+12}{3}
Dividing by 3 undoes the multiplication by 3.
x=\frac{4y}{3}+4
Divide 12+4y by 3.
-4y=12-3x
Subtract 3x from both sides.
\frac{-4y}{-4}=\frac{12-3x}{-4}
Divide both sides by -4.
y=\frac{12-3x}{-4}
Dividing by -4 undoes the multiplication by -4.
y=\frac{3x}{4}-3
Divide 12-3x by -4.
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