Solve for x
x=\frac{4\left(y-2\right)}{3}
Solve for y
y=\frac{3x}{4}+2
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3x=-8+4y
Add 4y to both sides.
3x=4y-8
The equation is in standard form.
\frac{3x}{3}=\frac{4y-8}{3}
Divide both sides by 3.
x=\frac{4y-8}{3}
Dividing by 3 undoes the multiplication by 3.
-4y=-8-3x
Subtract 3x from both sides.
-4y=-3x-8
The equation is in standard form.
\frac{-4y}{-4}=\frac{-3x-8}{-4}
Divide both sides by -4.
y=\frac{-3x-8}{-4}
Dividing by -4 undoes the multiplication by -4.
y=\frac{3x}{4}+2
Divide -8-3x by -4.
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Limits
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