Solve 3x-4+3x^2-4x+2/x

$$3 x - 4 + 3 x ^ { 2 } - 4 x + \frac { 2 } { x }$$

Evaluate

$$3x^{2}-x-4+\frac{2}{x}$$

Short Solution Steps

Combine 3x and -4x to get -x.

$$-x-4+3x^{2}+\frac{2}{x}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply -x-4+3x^{2} times \frac{x}{x}.

$$\frac{\left(-x-4+3x^{2}\right)x}{x}+\frac{2}{x}$$

Since \frac{\left(-x-4+3x^{2}\right)x}{x} and \frac{2}{x} have the same denominator, add them by adding their numerators.

$$\frac{\left(-x-4+3x^{2}\right)x+2}{x}$$

Do the multiplications in \left(-x-4+3x^{2}\right)x+2.

$$\frac{-x^{2}-4x+3x^{3}+2}{x}$$

Factor

$$\frac{3\left(x-1\right)\left(x-\frac{-\sqrt{7}-1}{3}\right)\left(x-\frac{\sqrt{7}-1}{3}\right)}{x}$$