Solve for x
x=\frac{2\left(z+2\right)}{3}
Solve for z
z=\frac{3x}{2}-2
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3x=4+2z
Add 2z to both sides.
3x=2z+4
The equation is in standard form.
\frac{3x}{3}=\frac{2z+4}{3}
Divide both sides by 3.
x=\frac{2z+4}{3}
Dividing by 3 undoes the multiplication by 3.
-2z=4-3x
Subtract 3x from both sides.
\frac{-2z}{-2}=\frac{4-3x}{-2}
Divide both sides by -2.
z=\frac{4-3x}{-2}
Dividing by -2 undoes the multiplication by -2.
z=\frac{3x}{2}-2
Divide 4-3x by -2.
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