Solve for x
x=\frac{2y}{3}+z+\frac{5}{3}
Solve for y
y=\frac{3x-3z-5}{2}
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3x-3z=5+2y
Add 2y to both sides.
3x=5+2y+3z
Add 3z to both sides.
3x=2y+3z+5
The equation is in standard form.
\frac{3x}{3}=\frac{2y+3z+5}{3}
Divide both sides by 3.
x=\frac{2y+3z+5}{3}
Dividing by 3 undoes the multiplication by 3.
x=\frac{2y}{3}+z+\frac{5}{3}
Divide 5+2y+3z by 3.
-2y-3z=5-3x
Subtract 3x from both sides.
-2y=5-3x+3z
Add 3z to both sides.
-2y=5+3z-3x
The equation is in standard form.
\frac{-2y}{-2}=\frac{5+3z-3x}{-2}
Divide both sides by -2.
y=\frac{5+3z-3x}{-2}
Dividing by -2 undoes the multiplication by -2.
y=\frac{3x-3z-5}{2}
Divide 5-3x+3z by -2.
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