Solve for x
x=\frac{2y+5}{3}
Solve for y
y=\frac{3x-5}{2}
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3x=5+2y
Add 2y to both sides.
3x=2y+5
The equation is in standard form.
\frac{3x}{3}=\frac{2y+5}{3}
Divide both sides by 3.
x=\frac{2y+5}{3}
Dividing by 3 undoes the multiplication by 3.
-2y=5-3x
Subtract 3x from both sides.
\frac{-2y}{-2}=\frac{5-3x}{-2}
Divide both sides by -2.
y=\frac{5-3x}{-2}
Dividing by -2 undoes the multiplication by -2.
y=\frac{3x-5}{2}
Divide 5-3x by -2.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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