Solve for x
x=\frac{2y}{3}+\frac{2z}{3}+11
Solve for y
y=\frac{3x}{2}-z-\frac{33}{2}
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3x=33+2z+2y
Add 2y to both sides.
3x=2y+2z+33
The equation is in standard form.
\frac{3x}{3}=\frac{2y+2z+33}{3}
Divide both sides by 3.
x=\frac{2y+2z+33}{3}
Dividing by 3 undoes the multiplication by 3.
x=\frac{2y}{3}+\frac{2z}{3}+11
Divide 33+2z+2y by 3.
-2y=33+2z-3x
Subtract 3x from both sides.
\frac{-2y}{-2}=\frac{33+2z-3x}{-2}
Divide both sides by -2.
y=\frac{33+2z-3x}{-2}
Dividing by -2 undoes the multiplication by -2.
y=\frac{3x}{2}-z-\frac{33}{2}
Divide 33+2z-3x by -2.
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