Solve for x
x=\frac{2\left(y-8\right)}{3}
Solve for y
y=\frac{3x}{2}+8
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3x=-16+2y
Add 2y to both sides.
3x=2y-16
The equation is in standard form.
\frac{3x}{3}=\frac{2y-16}{3}
Divide both sides by 3.
x=\frac{2y-16}{3}
Dividing by 3 undoes the multiplication by 3.
-2y=-16-3x
Subtract 3x from both sides.
-2y=-3x-16
The equation is in standard form.
\frac{-2y}{-2}=\frac{-3x-16}{-2}
Divide both sides by -2.
y=\frac{-3x-16}{-2}
Dividing by -2 undoes the multiplication by -2.
y=\frac{3x}{2}+8
Divide -16-3x by -2.
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