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3x+3=y
Add y to both sides. Anything plus zero gives itself.
3x=y-3
Subtract 3 from both sides.
\frac{3x}{3}=\frac{y-3}{3}
Divide both sides by 3.
x=\frac{y-3}{3}
Dividing by 3 undoes the multiplication by 3.
x=\frac{y}{3}-1
Divide y-3 by 3.
-y+3=-3x
Subtract 3x from both sides. Anything subtracted from zero gives its negation.
-y=-3x-3
Subtract 3 from both sides.
\frac{-y}{-1}=\frac{-3x-3}{-1}
Divide both sides by -1.
y=\frac{-3x-3}{-1}
Dividing by -1 undoes the multiplication by -1.
y=3x+3
Divide -3x-3 by -1.