Solve for d (complex solution)
\left\{\begin{matrix}d=-\frac{1-3x}{5y}\text{, }&y\neq 0\\d\in \mathrm{C}\text{, }&x=\frac{1}{3}\text{ and }y=0\end{matrix}\right.
Solve for d
\left\{\begin{matrix}d=-\frac{1-3x}{5y}\text{, }&y\neq 0\\d\in \mathrm{R}\text{, }&x=\frac{1}{3}\text{ and }y=0\end{matrix}\right.
Solve for x
x=\frac{5dy+1}{3}
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5yd=3x-1
Swap sides so that all variable terms are on the left hand side.
\frac{5yd}{5y}=\frac{3x-1}{5y}
Divide both sides by 5y.
d=\frac{3x-1}{5y}
Dividing by 5y undoes the multiplication by 5y.
5yd=3x-1
Swap sides so that all variable terms are on the left hand side.
\frac{5yd}{5y}=\frac{3x-1}{5y}
Divide both sides by 5y.
d=\frac{3x-1}{5y}
Dividing by 5y undoes the multiplication by 5y.
3x=5yd+1
Add 1 to both sides.
3x=5dy+1
The equation is in standard form.
\frac{3x}{3}=\frac{5dy+1}{3}
Divide both sides by 3.
x=\frac{5dy+1}{3}
Dividing by 3 undoes the multiplication by 3.
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