Solve 3x(2)^2*3+2*3*(2)^2+(2)^2

$$3 x ( 2 ) ^ { 2 } \times 3 + 2 \times 3 \times ( 2 ) ^ { 2 } + ( 2 ) ^ { 2 }$$

Evaluate

$$36x+28$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$3x\times 2^{2}\times 3+2^{3}\times 3+2^{2}$$

Calculate 2 to the power of 2 and get 4.

$$3x\times 4\times 3+2^{3}\times 3+2^{2}$$

Multiply 3 and 4 to get 12.

$$12x\times 3+2^{3}\times 3+2^{2}$$

Multiply 12 and 3 to get 36.

$$36x+2^{3}\times 3+2^{2}$$

Calculate 2 to the power of 3 and get 8.

$$36x+8\times 3+2^{2}$$

Multiply 8 and 3 to get 24.

$$36x+24+2^{2}$$

Calculate 2 to the power of 2 and get 4.

$$36x+24+4$$

Add 24 and 4 to get 28.

$$36x+28$$

Factor

$$4\left(9x+7\right)$$

Solution Steps

Factor out 4.

$$4\left(9x+7\right)$$

Consider 9x+6+1. Multiply and combine like terms.

$$9x+7$$

Rewrite the complete factored expression.

$$4\left(9x+7\right)$$