Solve 3x(-4-2+10)+120=40+2x/3

$$3 x ( - 4 - 2 + 10 ) + 120 = \frac { 40 + 2 x } { 3 }$$

Solve for x

$$x = -\frac{160}{17} = -9\frac{7}{17} \approx -9.411764706$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 3.

$$9x\left(-4-2+10\right)+360=40+2x$$

Subtract 2 from -4 to get -6.

$$9x\left(-6+10\right)+360=40+2x$$

Add -6 and 10 to get 4.

$$9x\times 4+360=40+2x$$

Multiply 9 and 4 to get 36.

$$36x+360=40+2x$$

Subtract 2x from both sides.

$$36x+360-2x=40$$

Combine 36x and -2x to get 34x.

$$34x+360=40$$

Subtract 360 from both sides.

$$34x=40-360$$

Subtract 360 from 40 to get -320.

$$34x=-320$$

Divide both sides by 34.

$$x=\frac{-320}{34}$$

Reduce the fraction \frac{-320}{34} to lowest terms by extracting and canceling out 2.

$$x=-\frac{160}{17}$$