Solve 3x*2x=3x+2(R

$$3 x \cdot 2 x = 3 x + 2 ( R$$

Solve for R

$$R=\frac{3x\left(2x-1\right)}{2}$$

Steps for Solving Linear Equation

Multiply x and x to get x^{2}.

$$3x^{2}\times 2=3x+2R$$

Multiply 3 and 2 to get 6.

$$6x^{2}=3x+2R$$

Swap sides so that all variable terms are on the left hand side.

$$3x+2R=6x^{2}$$

Subtract 3x from both sides.

$$2R=6x^{2}-3x$$

Divide both sides by 2.

$$\frac{2R}{2}=\frac{3x\left(2x-1\right)}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$R=\frac{3x\left(2x-1\right)}{2}$$

Solve for x (complex solution)

$$x=\frac{\sqrt{48R+9}}{12}+\frac{1}{4}$$

$$x=-\frac{\sqrt{48R+9}}{12}+\frac{1}{4}$$

Solve for x

$$x=\frac{\sqrt{48R+9}}{12}+\frac{1}{4}$$

$$x=-\frac{\sqrt{48R+9}}{12}+\frac{1}{4}\text{, }R\geq -\frac{3}{16}$$