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3\left(x^{9}+9x^{8}+18x^{7}\right)
Factor out 3.
x^{7}\left(x^{2}+9x+18\right)
Consider x^{9}+9x^{8}+18x^{7}. Factor out x^{7}.
a+b=9 ab=1\times 18=18
Consider x^{2}+9x+18. Factor the expression by grouping. First, the expression needs to be rewritten as x^{2}+ax+bx+18. To find a and b, set up a system to be solved.
1,18 2,9 3,6
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 18.
1+18=19 2+9=11 3+6=9
Calculate the sum for each pair.
a=3 b=6
The solution is the pair that gives sum 9.
\left(x^{2}+3x\right)+\left(6x+18\right)
Rewrite x^{2}+9x+18 as \left(x^{2}+3x\right)+\left(6x+18\right).
x\left(x+3\right)+6\left(x+3\right)
Factor out x in the first and 6 in the second group.
\left(x+3\right)\left(x+6\right)
Factor out common term x+3 by using distributive property.
3x^{7}\left(x+3\right)\left(x+6\right)
Rewrite the complete factored expression.