Solve 3x^4-4x^3-3x^-1divx-1

$$3 x ^ { 4 } - 4 x ^ { 3 } - 3 x ^ { - 1 } \div x - 1$$

Evaluate

$$3x^{4}-4x^{3}-1-\frac{3}{x^{2}}$$

Short Solution Steps

To divide powers of the same base, subtract the numerator's exponent from the denominator's exponent.

$$3x^{4}-4x^{3}-\frac{3}{x^{2}}-1$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 3x^{4}-4x^{3}-1 times \frac{x^{2}}{x^{2}}.

$$\frac{\left(3x^{4}-4x^{3}-1\right)x^{2}}{x^{2}}-\frac{3}{x^{2}}$$

Since \frac{\left(3x^{4}-4x^{3}-1\right)x^{2}}{x^{2}} and \frac{3}{x^{2}} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\left(3x^{4}-4x^{3}-1\right)x^{2}-3}{x^{2}}$$

Do the multiplications in \left(3x^{4}-4x^{3}-1\right)x^{2}-3.

$$\frac{3x^{6}-4x^{5}-x^{2}-3}{x^{2}}$$

Factor

$$\frac{3x^{6}-4x^{5}-x^{2}-3}{x^{2}}$$