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3\left(x^{4}+11x^{3}+28x^{2}\right)
Factor out 3.
x^{2}\left(x^{2}+11x+28\right)
Consider x^{4}+11x^{3}+28x^{2}. Factor out x^{2}.
a+b=11 ab=1\times 28=28
Consider x^{2}+11x+28. Factor the expression by grouping. First, the expression needs to be rewritten as x^{2}+ax+bx+28. To find a and b, set up a system to be solved.
1,28 2,14 4,7
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 28.
1+28=29 2+14=16 4+7=11
Calculate the sum for each pair.
a=4 b=7
The solution is the pair that gives sum 11.
\left(x^{2}+4x\right)+\left(7x+28\right)
Rewrite x^{2}+11x+28 as \left(x^{2}+4x\right)+\left(7x+28\right).
x\left(x+4\right)+7\left(x+4\right)
Factor out x in the first and 7 in the second group.
\left(x+4\right)\left(x+7\right)
Factor out common term x+4 by using distributive property.
3x^{2}\left(x+4\right)\left(x+7\right)
Rewrite the complete factored expression.