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x\left(3x^{2}-5x+2\right)
Factor out x.
a+b=-5 ab=3\times 2=6
Consider 3x^{2}-5x+2. Factor the expression by grouping. First, the expression needs to be rewritten as 3x^{2}+ax+bx+2. To find a and b, set up a system to be solved.
-1,-6 -2,-3
Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 6.
-1-6=-7 -2-3=-5
Calculate the sum for each pair.
a=-3 b=-2
The solution is the pair that gives sum -5.
\left(3x^{2}-3x\right)+\left(-2x+2\right)
Rewrite 3x^{2}-5x+2 as \left(3x^{2}-3x\right)+\left(-2x+2\right).
3x\left(x-1\right)-2\left(x-1\right)
Factor out 3x in the first and -2 in the second group.
\left(x-1\right)\left(3x-2\right)
Factor out common term x-1 by using distributive property.
x\left(x-1\right)\left(3x-2\right)
Rewrite the complete factored expression.