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x^{2}\left(3x+1\right)+12\left(3x+1\right)
Do the grouping 3x^{3}+x^{2}+36x+12=\left(3x^{3}+x^{2}\right)+\left(36x+12\right), and factor out x^{2} in the first and 12 in the second group.
\left(3x+1\right)\left(x^{2}+12\right)
Factor out common term 3x+1 by using distributive property. Polynomial x^{2}+12 is not factored since it does not have any rational roots.