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3x^{2}=21
Add 21 to both sides. Anything plus zero gives itself.
x^{2}=\frac{21}{3}
Divide both sides by 3.
x^{2}=7
Divide 21 by 3 to get 7.
x=\sqrt{7} x=-\sqrt{7}
Take the square root of both sides of the equation.
3x^{2}-21=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\times 3\left(-21\right)}}{2\times 3}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 3 for a, 0 for b, and -21 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 3\left(-21\right)}}{2\times 3}
Square 0.
x=\frac{0±\sqrt{-12\left(-21\right)}}{2\times 3}
Multiply -4 times 3.
x=\frac{0±\sqrt{252}}{2\times 3}
Multiply -12 times -21.
x=\frac{0±6\sqrt{7}}{2\times 3}
Take the square root of 252.
x=\frac{0±6\sqrt{7}}{6}
Multiply 2 times 3.
x=\sqrt{7}
Now solve the equation x=\frac{0±6\sqrt{7}}{6} when ± is plus.
x=-\sqrt{7}
Now solve the equation x=\frac{0±6\sqrt{7}}{6} when ± is minus.
x=\sqrt{7} x=-\sqrt{7}
The equation is now solved.