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3x^{2}=526+14
Add 14 to both sides.
3x^{2}=540
Add 526 and 14 to get 540.
x^{2}=\frac{540}{3}
Divide both sides by 3.
x^{2}=180
Divide 540 by 3 to get 180.
x=6\sqrt{5} x=-6\sqrt{5}
Take the square root of both sides of the equation.
3x^{2}-14-526=0
Subtract 526 from both sides.
3x^{2}-540=0
Subtract 526 from -14 to get -540.
x=\frac{0±\sqrt{0^{2}-4\times 3\left(-540\right)}}{2\times 3}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 3 for a, 0 for b, and -540 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 3\left(-540\right)}}{2\times 3}
Square 0.
x=\frac{0±\sqrt{-12\left(-540\right)}}{2\times 3}
Multiply -4 times 3.
x=\frac{0±\sqrt{6480}}{2\times 3}
Multiply -12 times -540.
x=\frac{0±36\sqrt{5}}{2\times 3}
Take the square root of 6480.
x=\frac{0±36\sqrt{5}}{6}
Multiply 2 times 3.
x=6\sqrt{5}
Now solve the equation x=\frac{0±36\sqrt{5}}{6} when ± is plus.
x=-6\sqrt{5}
Now solve the equation x=\frac{0±36\sqrt{5}}{6} when ± is minus.
x=6\sqrt{5} x=-6\sqrt{5}
The equation is now solved.