Solve 3x^2+7=3

$$3 x ^ { 2 } + 7 = 3$$

Solve for x (complex solution)

$$x=-\frac{2\sqrt{3}i}{3}\approx -0-1.154700538i$$

$$x=\frac{2\sqrt{3}i}{3}\approx 1.154700538i$$

Steps by Finding Square Root

Subtract 7 from both sides.

$$3x^{2}=3-7$$

Subtract 7 from 3 to get -4.

$$3x^{2}=-4$$

Divide both sides by 3.

$$x^{2}=-\frac{4}{3}$$

The equation is now solved.

$$x=\frac{2\sqrt{3}i}{3} x=-\frac{2\sqrt{3}i}{3}$$

Steps Using the Quadratic Formula

Subtract 3 from both sides.

$$3x^{2}+7-3=0$$

Subtract 3 from 7 to get 4.

$$3x^{2}+4=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 3 for a, 0 for b, and 4 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 3\times 4}}{2\times 3}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 3\times 4}}{2\times 3}$$

Multiply -4 times 3.

$$x=\frac{0±\sqrt{-12\times 4}}{2\times 3}$$

Multiply -12 times 4.

$$x=\frac{0±\sqrt{-48}}{2\times 3}$$

Take the square root of -48.

$$x=\frac{0±4\sqrt{3}i}{2\times 3}$$

Multiply 2 times 3.

$$x=\frac{0±4\sqrt{3}i}{6}$$

Now solve the equation x=\frac{0±4\sqrt{3}i}{6} when ± is plus.

$$x=\frac{2\sqrt{3}i}{3}$$

Now solve the equation x=\frac{0±4\sqrt{3}i}{6} when ± is minus.

$$x=-\frac{2\sqrt{3}i}{3}$$

The equation is now solved.

$$x=\frac{2\sqrt{3}i}{3} x=-\frac{2\sqrt{3}i}{3}$$