Solve 3x^2+6y+9=0

$$3 x ^ { 2 } + 6 y + 9 = 0$$

Solve for y

$$y=\frac{-x^{2}-3}{2}$$

Steps for Solving Linear Equation

Subtract 3x^{2} from both sides. Anything subtracted from zero gives its negation.

$$6y+9=-3x^{2}$$

Subtract 9 from both sides.

$$6y=-3x^{2}-9$$

Divide both sides by 6.

$$\frac{6y}{6}=\frac{-3x^{2}-9}{6}$$

Dividing by 6 undoes the multiplication by 6.

$$y=\frac{-3x^{2}-9}{6}$$

Divide -3x^{2}-9 by 6.

$$y=\frac{-x^{2}-3}{2}$$

Solve for x (complex solution)

$$x=-\sqrt{-2y-3}$$

$$x=\sqrt{-2y-3}$$

Solve for x

$$x=\sqrt{-2y-3}$$

$$x=-\sqrt{-2y-3}\text{, }y\leq -\frac{3}{2}$$