Solve for y
y=\frac{z-3x^{2}}{5}
Solve for x
x=\frac{\sqrt{3\left(z-5y\right)}}{3}
x=-\frac{\sqrt{3\left(z-5y\right)}}{3}\text{, }y\leq \frac{z}{5}
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5y=z-3x^{2}
Subtract 3x^{2} from both sides.
\frac{5y}{5}=\frac{z-3x^{2}}{5}
Divide both sides by 5.
y=\frac{z-3x^{2}}{5}
Dividing by 5 undoes the multiplication by 5.
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