Solve 3x^2+5y+3=11

$$3 x ^ { 2 } + 5 y + 3 = 11$$

Solve for y

$$y=\frac{8-3x^{2}}{5}$$

Steps for Solving Linear Equation

Subtract 3x^{2} from both sides.

$$5y+3=11-3x^{2}$$

Subtract 3 from both sides.

$$5y=11-3x^{2}-3$$

Subtract 3 from 11 to get 8.

$$5y=8-3x^{2}$$

Divide both sides by 5.

$$\frac{5y}{5}=\frac{8-3x^{2}}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$y=\frac{8-3x^{2}}{5}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{24-15y}}{3}$$

$$x=\frac{\sqrt{24-15y}}{3}$$

Solve for x

$$x=\frac{\sqrt{24-15y}}{3}$$

$$x=-\frac{\sqrt{24-15y}}{3}\text{, }y\leq \frac{8}{5}$$