Solve 3x^2+5-4y=7

$$3 x ^ { 2 } + 5 - 4 y = 7$$

Solve for y

$$y=\frac{3x^{2}}{4}-\frac{1}{2}$$

Steps for Solving Linear Equation

Subtract 3x^{2} from both sides.

$$5-4y=7-3x^{2}$$

Subtract 5 from both sides.

$$-4y=7-3x^{2}-5$$

Subtract 5 from 7 to get 2.

$$-4y=2-3x^{2}$$

Divide both sides by -4.

$$\frac{-4y}{-4}=\frac{2-3x^{2}}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$y=\frac{2-3x^{2}}{-4}$$

Divide 2-3x^{2} by -4.

$$y=\frac{3x^{2}}{4}-\frac{1}{2}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{12y+6}}{3}$$

$$x=\frac{\sqrt{12y+6}}{3}$$

Solve for x

$$x=\frac{\sqrt{12y+6}}{3}$$

$$x=-\frac{\sqrt{12y+6}}{3}\text{, }y\geq -\frac{1}{2}$$