Solve 3x^2+5=2

$$3 x ^ { 2 } + 5 = 2$$

Solve for x (complex solution)

$$x=-i$$

$$x=i$$

Steps by Finding Square Root

Subtract 5 from both sides.

$$3x^{2}=2-5$$

Subtract 5 from 2 to get -3.

$$3x^{2}=-3$$

Divide both sides by 3.

$$x^{2}=\frac{-3}{3}$$

Divide -3 by 3 to get -1.

$$x^{2}=-1$$

The equation is now solved.

$$x=i x=-i$$

Steps Using the Quadratic Formula

Subtract 2 from both sides.

$$3x^{2}+5-2=0$$

Subtract 2 from 5 to get 3.

$$3x^{2}+3=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 3 for a, 0 for b, and 3 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 3\times 3}}{2\times 3}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 3\times 3}}{2\times 3}$$

Multiply -4 times 3.

$$x=\frac{0±\sqrt{-12\times 3}}{2\times 3}$$

Multiply -12 times 3.

$$x=\frac{0±\sqrt{-36}}{2\times 3}$$

Take the square root of -36.

$$x=\frac{0±6i}{2\times 3}$$

Multiply 2 times 3.

$$x=\frac{0±6i}{6}$$

Now solve the equation x=\frac{0±6i}{6} when ± is plus.

$$x=i$$

Now solve the equation x=\frac{0±6i}{6} when ± is minus.

$$x=-i$$

The equation is now solved.

$$x=i x=-i$$