Solve 3x^2+4y+30=0}

$$3 x ^ { 2 } + 4 y + 30 = 0 \}$$

Solve for y

$$y=-\frac{3x^{2}}{4}-\frac{15}{2}$$

Steps for Solving Linear Equation

Subtract 3x^{2} from both sides. Anything subtracted from zero gives its negation.

$$4y+30=-3x^{2}$$

Subtract 30 from both sides.

$$4y=-3x^{2}-30$$

Divide both sides by 4.

$$\frac{4y}{4}=\frac{-3x^{2}-30}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$y=\frac{-3x^{2}-30}{4}$$

Divide -3x^{2}-30 by 4.

$$y=-\frac{3x^{2}}{4}-\frac{15}{2}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{-12y-90}}{3}$$

$$x=\frac{\sqrt{-12y-90}}{3}$$

Solve for x

$$x=\frac{\sqrt{-12y-90}}{3}$$

$$x=-\frac{\sqrt{-12y-90}}{3}\text{, }y\leq -\frac{15}{2}$$