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7x^{2}=2500
Combine 3x^{2} and 4x^{2} to get 7x^{2}.
x^{2}=\frac{2500}{7}
Divide both sides by 7.
x=\frac{50\sqrt{7}}{7} x=-\frac{50\sqrt{7}}{7}
Take the square root of both sides of the equation.
7x^{2}=2500
Combine 3x^{2} and 4x^{2} to get 7x^{2}.
7x^{2}-2500=0
Subtract 2500 from both sides.
x=\frac{0±\sqrt{0^{2}-4\times 7\left(-2500\right)}}{2\times 7}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 7 for a, 0 for b, and -2500 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 7\left(-2500\right)}}{2\times 7}
Square 0.
x=\frac{0±\sqrt{-28\left(-2500\right)}}{2\times 7}
Multiply -4 times 7.
x=\frac{0±\sqrt{70000}}{2\times 7}
Multiply -28 times -2500.
x=\frac{0±100\sqrt{7}}{2\times 7}
Take the square root of 70000.
x=\frac{0±100\sqrt{7}}{14}
Multiply 2 times 7.
x=\frac{50\sqrt{7}}{7}
Now solve the equation x=\frac{0±100\sqrt{7}}{14} when ± is plus.
x=-\frac{50\sqrt{7}}{7}
Now solve the equation x=\frac{0±100\sqrt{7}}{14} when ± is minus.
x=\frac{50\sqrt{7}}{7} x=-\frac{50\sqrt{7}}{7}
The equation is now solved.