Solve 3x^2+30x+10-y=0

$$3 x ^ { 2 } + 30 x + 10 - y = 0$$

Solve for y

$$y=3x^{2}+30x+10$$

Steps for Solving Linear Equation

Subtract 3x^{2} from both sides. Anything subtracted from zero gives its negation.

$$30x+10-y=-3x^{2}$$

Subtract 30x from both sides.

$$10-y=-3x^{2}-30x$$

Subtract 10 from both sides.

$$-y=-3x^{2}-30x-10$$

Divide both sides by -1.

$$\frac{-y}{-1}=\frac{-3x^{2}-30x-10}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$y=\frac{-3x^{2}-30x-10}{-1}$$

Divide -3x^{2}-30x-10 by -1.

$$y=3x^{2}+30x+10$$

Solve for x (complex solution)

$$x=\frac{\sqrt{3y+195}}{3}-5$$

$$x=-\frac{\sqrt{3y+195}}{3}-5$$

Solve for x

$$x=\frac{\sqrt{3y+195}}{3}-5$$

$$x=-\frac{\sqrt{3y+195}}{3}-5\text{, }y\geq -65$$