Solve 3x^2+24y+56=0

$$3 x ^ { 2 } + 24 y + 56 = 0$$

Solve for y

$$y=-\frac{x^{2}}{8}-\frac{7}{3}$$

Steps for Solving Linear Equation

Subtract 3x^{2} from both sides. Anything subtracted from zero gives its negation.

$$24y+56=-3x^{2}$$

Subtract 56 from both sides.

$$24y=-3x^{2}-56$$

Divide both sides by 24.

$$\frac{24y}{24}=\frac{-3x^{2}-56}{24}$$

Dividing by 24 undoes the multiplication by 24.

$$y=\frac{-3x^{2}-56}{24}$$

Divide -3x^{2}-56 by 24.

$$y=-\frac{x^{2}}{8}-\frac{7}{3}$$

Solve for x (complex solution)

$$x=-\frac{2\sqrt{-18y-42}}{3}$$

$$x=\frac{2\sqrt{-18y-42}}{3}$$

Solve for x

$$x=\frac{2\sqrt{-18y-42}}{3}$$

$$x=-\frac{2\sqrt{-18y-42}}{3}\text{, }y\leq -\frac{7}{3}$$