Solve 3x^2+2y-1=16

$$3 x ^ { 2 } + 2 y - 1 = 16$$

Solve for y

$$y=\frac{17-3x^{2}}{2}$$

Steps for Solving Linear Equation

Subtract 3x^{2} from both sides.

$$2y-1=16-3x^{2}$$

Add 1 to both sides.

$$2y=16-3x^{2}+1$$

Add 16 and 1 to get 17.

$$2y=17-3x^{2}$$

Divide both sides by 2.

$$\frac{2y}{2}=\frac{17-3x^{2}}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$y=\frac{17-3x^{2}}{2}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{51-6y}}{3}$$

$$x=\frac{\sqrt{51-6y}}{3}$$

Solve for x

$$x=\frac{\sqrt{51-6y}}{3}$$

$$x=-\frac{\sqrt{51-6y}}{3}\text{, }y\leq \frac{17}{2}$$