Solve 3x^2+2y+5=y

$$3 x ^ { 2 } + 2 y + 5 = y$$

Solve for y

$$y=-3x^{2}-5$$

Solution Steps

Subtract y from both sides.

$$3x^{2}+2y+5-y=0$$

Combine 2y and -y to get y.

$$3x^{2}+y+5=0$$

Subtract 3x^{2} from both sides. Anything subtracted from zero gives its negation.

$$y+5=-3x^{2}$$

Subtract 5 from both sides.

$$y=-3x^{2}-5$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{-3y-15}}{3}$$

$$x=\frac{\sqrt{-3y-15}}{3}$$

Solve for x

$$x=\frac{\sqrt{-3y-15}}{3}$$

$$x=-\frac{\sqrt{-3y-15}}{3}\text{, }y\leq -5$$