Solve 3x^2+2x^2+x^2+1=1

$$3 x ^ { 2 } + 2 x ^ { 2 } + x ^ { 2 } + 1 = 1$$

Solve for x

$$x=0$$

Steps by Finding Square Root

Combine 3x^{2} and 2x^{2} to get 5x^{2}.

$$5x^{2}+x^{2}+1=1$$

Combine 5x^{2} and x^{2} to get 6x^{2}.

$$6x^{2}+1=1$$

Subtract 1 from both sides.

$$6x^{2}=1-1$$

Subtract 1 from 1 to get 0.

$$6x^{2}=0$$

Divide both sides by 6. Zero divided by any non-zero number gives zero.

$$x^{2}=0$$

Take the square root of both sides of the equation.

$$x=0 x=0$$

The equation is now solved. Solutions are the same.

$$x=0$$

Steps Using the Quadratic Formula

Combine 3x^{2} and 2x^{2} to get 5x^{2}.

$$5x^{2}+x^{2}+1=1$$

Combine 5x^{2} and x^{2} to get 6x^{2}.

$$6x^{2}+1=1$$

Subtract 1 from both sides.

$$6x^{2}+1-1=0$$

Subtract 1 from 1 to get 0.

$$6x^{2}=0$$

Divide both sides by 6. Zero divided by any non-zero number gives zero.

$$x^{2}=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}}}{2}$$

Take the square root of 0^{2}.

$$x=\frac{0±0}{2}$$

Divide 0 by 2.

$$x=0$$