Solve 3x^2+2b-4=0

$$3 x ^ { 2 } + 2 b - 4 = 0$$

Solve for b

$$b=-\frac{3x^{2}}{2}+2$$

Steps for Solving Linear Equation

Subtract 3x^{2} from both sides. Anything subtracted from zero gives its negation.

$$2b-4=-3x^{2}$$

Add 4 to both sides.

$$2b=-3x^{2}+4$$

The equation is in standard form.

$$2b=4-3x^{2}$$

Divide both sides by 2.

$$\frac{2b}{2}=\frac{4-3x^{2}}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$b=\frac{4-3x^{2}}{2}$$

Divide -3x^{2}+4 by 2.

$$b=-\frac{3x^{2}}{2}+2$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{12-6b}}{3}$$

$$x=\frac{\sqrt{12-6b}}{3}$$

Solve for x

$$x=\frac{\sqrt{12-6b}}{3}$$

$$x=-\frac{\sqrt{12-6b}}{3}\text{, }b\leq 2$$