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x\left(3x+12\right)=0
Factor out x.
x=0 x=-4
To find equation solutions, solve x=0 and 3x+12=0.
3x^{2}+12x=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-12±\sqrt{12^{2}}}{2\times 3}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 3 for a, 12 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-12±12}{2\times 3}
Take the square root of 12^{2}.
x=\frac{-12±12}{6}
Multiply 2 times 3.
x=\frac{0}{6}
Now solve the equation x=\frac{-12±12}{6} when ± is plus. Add -12 to 12.
x=0
Divide 0 by 6.
x=-\frac{24}{6}
Now solve the equation x=\frac{-12±12}{6} when ± is minus. Subtract 12 from -12.
x=-4
Divide -24 by 6.
x=0 x=-4
The equation is now solved.
3x^{2}+12x=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
\frac{3x^{2}+12x}{3}=\frac{0}{3}
Divide both sides by 3.
x^{2}+\frac{12}{3}x=\frac{0}{3}
Dividing by 3 undoes the multiplication by 3.
x^{2}+4x=\frac{0}{3}
Divide 12 by 3.
x^{2}+4x=0
Divide 0 by 3.
x^{2}+4x+2^{2}=2^{2}
Divide 4, the coefficient of the x term, by 2 to get 2. Then add the square of 2 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+4x+4=4
Square 2.
\left(x+2\right)^{2}=4
Factor x^{2}+4x+4. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+2\right)^{2}}=\sqrt{4}
Take the square root of both sides of the equation.
x+2=2 x+2=-2
Simplify.
x=0 x=-4
Subtract 2 from both sides of the equation.