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3x^{2}+1-2=-x^{2}
Subtract 2 from both sides.
3x^{2}-1=-x^{2}
Subtract 2 from 1 to get -1.
3x^{2}-1+x^{2}=0
Add x^{2} to both sides.
4x^{2}-1=0
Combine 3x^{2} and x^{2} to get 4x^{2}.
\left(2x-1\right)\left(2x+1\right)=0
Consider 4x^{2}-1. Rewrite 4x^{2}-1 as \left(2x\right)^{2}-1^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
x=\frac{1}{2} x=-\frac{1}{2}
To find equation solutions, solve 2x-1=0 and 2x+1=0.
3x^{2}+1+x^{2}=2
Add x^{2} to both sides.
4x^{2}+1=2
Combine 3x^{2} and x^{2} to get 4x^{2}.
4x^{2}=2-1
Subtract 1 from both sides.
4x^{2}=1
Subtract 1 from 2 to get 1.
x^{2}=\frac{1}{4}
Divide both sides by 4.
x=\frac{1}{2} x=-\frac{1}{2}
Take the square root of both sides of the equation.
3x^{2}+1-2=-x^{2}
Subtract 2 from both sides.
3x^{2}-1=-x^{2}
Subtract 2 from 1 to get -1.
3x^{2}-1+x^{2}=0
Add x^{2} to both sides.
4x^{2}-1=0
Combine 3x^{2} and x^{2} to get 4x^{2}.
x=\frac{0±\sqrt{0^{2}-4\times 4\left(-1\right)}}{2\times 4}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 4 for a, 0 for b, and -1 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 4\left(-1\right)}}{2\times 4}
Square 0.
x=\frac{0±\sqrt{-16\left(-1\right)}}{2\times 4}
Multiply -4 times 4.
x=\frac{0±\sqrt{16}}{2\times 4}
Multiply -16 times -1.
x=\frac{0±4}{2\times 4}
Take the square root of 16.
x=\frac{0±4}{8}
Multiply 2 times 4.
x=\frac{1}{2}
Now solve the equation x=\frac{0±4}{8} when ± is plus. Reduce the fraction \frac{4}{8} to lowest terms by extracting and canceling out 4.
x=-\frac{1}{2}
Now solve the equation x=\frac{0±4}{8} when ± is minus. Reduce the fraction \frac{-4}{8} to lowest terms by extracting and canceling out 4.
x=\frac{1}{2} x=-\frac{1}{2}
The equation is now solved.