Solve 3x^-4y^3*8x^-4y^-6

$$3 x ^ { - 4 } y ^ { 3 } \cdot 8 x ^ { - 4 } y ^ { - 6 }$$

Evaluate

$$\frac{24}{y^{3}x^{8}}$$

Steps Using Commutative Property of Multiplication

Use the rules of exponents to simplify the expression.

$$3^{1}x^{-4}y^{3}\times 8^{1}x^{-4}y^{-6}$$

Use the Commutative Property of Multiplication.

$$3^{1}\times 8^{1}x^{-4}x^{-4}y^{3}y^{-6}$$

To multiply powers of the same base, add their exponents.

$$3^{1}\times 8^{1}x^{-4-4}y^{3-6}$$

Add the exponents -4 and -4.

$$3^{1}\times 8^{1}x^{-8}y^{3-6}$$

Add the exponents 3 and -6.

$$3^{1}\times 8^{1}\times \frac{1}{x^{8}}y^{-3}$$

Multiply 3 times 8.

$$24\times \frac{1}{x^{8}}\times \frac{1}{y^{3}}$$

Differentiate w.r.t. x

$$-\frac{192}{y^{3}x^{9}}$$