Solve for x
x=\frac{2\left(y+4\right)}{3}
Solve for y
y=\frac{3x}{2}-4
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3x=2y+8
The equation is in standard form.
\frac{3x}{3}=\frac{2y+8}{3}
Divide both sides by 3.
x=\frac{2y+8}{3}
Dividing by 3 undoes the multiplication by 3.
8+2y=3x
Swap sides so that all variable terms are on the left hand side.
2y=3x-8
Subtract 8 from both sides.
\frac{2y}{2}=\frac{3x-8}{2}
Divide both sides by 2.
y=\frac{3x-8}{2}
Dividing by 2 undoes the multiplication by 2.
y=\frac{3x}{2}-4
Divide 3x-8 by 2.
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