Solve for x
x = \frac{43}{20} = 2\frac{3}{20} = 2.15
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3x=4-\frac{-15}{7}+\frac{1}{7}x
Subtract 1 from 5 to get 4.
3x=4-\left(-\frac{15}{7}\right)+\frac{1}{7}x
Fraction \frac{-15}{7} can be rewritten as -\frac{15}{7} by extracting the negative sign.
3x=4+\frac{15}{7}+\frac{1}{7}x
The opposite of -\frac{15}{7} is \frac{15}{7}.
3x=\frac{28}{7}+\frac{15}{7}+\frac{1}{7}x
Convert 4 to fraction \frac{28}{7}.
3x=\frac{28+15}{7}+\frac{1}{7}x
Since \frac{28}{7} and \frac{15}{7} have the same denominator, add them by adding their numerators.
3x=\frac{43}{7}+\frac{1}{7}x
Add 28 and 15 to get 43.
3x-\frac{1}{7}x=\frac{43}{7}
Subtract \frac{1}{7}x from both sides.
\frac{20}{7}x=\frac{43}{7}
Combine 3x and -\frac{1}{7}x to get \frac{20}{7}x.
x=\frac{43}{7}\times \frac{7}{20}
Multiply both sides by \frac{7}{20}, the reciprocal of \frac{20}{7}.
x=\frac{43\times 7}{7\times 20}
Multiply \frac{43}{7} times \frac{7}{20} by multiplying numerator times numerator and denominator times denominator.
x=\frac{43}{20}
Cancel out 7 in both numerator and denominator.
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Limits
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