Solve for x
x=\frac{4\left(y+3\right)}{3}
Solve for y
y=\frac{3\left(x-4\right)}{4}
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3x=4y+12
The equation is in standard form.
\frac{3x}{3}=\frac{4y+12}{3}
Divide both sides by 3.
x=\frac{4y+12}{3}
Dividing by 3 undoes the multiplication by 3.
x=\frac{4y}{3}+4
Divide 12+4y by 3.
4y+12=3x
Swap sides so that all variable terms are on the left hand side.
4y=3x-12
Subtract 12 from both sides.
\frac{4y}{4}=\frac{3x-12}{4}
Divide both sides by 4.
y=\frac{3x-12}{4}
Dividing by 4 undoes the multiplication by 4.
y=\frac{3x}{4}-3
Divide -12+3x by 4.
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