Solve for x
x=\frac{\sqrt[3]{3}}{9}\approx 0.160249952
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3x=\frac{1}{\sqrt[3]{9}}
The equation is in standard form.
\frac{3x}{3}=\frac{1}{3\times 3^{\frac{2}{3}}}
Divide both sides by 3.
x=\frac{1}{3\times 3^{\frac{2}{3}}}
Dividing by 3 undoes the multiplication by 3.
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