Solve 3x+B^2=5

$$3 x + B ^ { 2 } = 5$$

Solve for x

$$x=\frac{5-B^{2}}{3}$$

Steps for Solving Linear Equation

Subtract B^{2} from both sides.

$$3x=5-B^{2}$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{5-B^{2}}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{5-B^{2}}{3}$$

Solve for B (complex solution)

$$B=-\sqrt{5-3x}$$

$$B=\sqrt{5-3x}$$

Solve for B

$$B=\sqrt{5-3x}$$

$$B=-\sqrt{5-3x}\text{, }x\leq \frac{5}{3}$$