Solve for x
x=\frac{47}{3}-3z
Solve for z
z=-\frac{x}{3}+\frac{47}{9}
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3x=47-9z
Subtract 9z from both sides.
\frac{3x}{3}=\frac{47-9z}{3}
Divide both sides by 3.
x=\frac{47-9z}{3}
Dividing by 3 undoes the multiplication by 3.
x=\frac{47}{3}-3z
Divide 47-9z by 3.
9z=47-3x
Subtract 3x from both sides.
\frac{9z}{9}=\frac{47-3x}{9}
Divide both sides by 9.
z=\frac{47-3x}{9}
Dividing by 9 undoes the multiplication by 9.
z=-\frac{x}{3}+\frac{47}{9}
Divide 47-3x by 9.
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