Solve for x
x=-3y-\frac{2}{3}
Solve for y
y=-\frac{x}{3}-\frac{2}{9}
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3x=-2-9y
Subtract 9y from both sides.
3x=-9y-2
The equation is in standard form.
\frac{3x}{3}=\frac{-9y-2}{3}
Divide both sides by 3.
x=\frac{-9y-2}{3}
Dividing by 3 undoes the multiplication by 3.
x=-3y-\frac{2}{3}
Divide -2-9y by 3.
9y=-2-3x
Subtract 3x from both sides.
9y=-3x-2
The equation is in standard form.
\frac{9y}{9}=\frac{-3x-2}{9}
Divide both sides by 9.
y=\frac{-3x-2}{9}
Dividing by 9 undoes the multiplication by 9.
y=-\frac{x}{3}-\frac{2}{9}
Divide -2-3x by 9.
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